2. Stereochemistry & Isomerism
Stereoisomers share the same connectivity but differ in 3D arrangement — and that difference can decide whether a molecule is a medicine or a poison. Stereochemistry is the study of that spatial language.
Constitutional Isomers and Cis–Trans
Constitutional isomers differ in connectivity (1-butene vs 2-methylpropene). Cis–trans isomers share connectivity but differ across a rigid double bond: in cis-2-butene both methyl groups sit on the same side; in trans-2-butene they oppose.
Chirality and Enantiomers
A carbon bonded to four different groups is a stereocenter, making the molecule chiral — non-superimposable on its mirror image. The two mirror images are enantiomers (e.g., the two forms of 2-butanol, $\text{CH}_3\text{–CH}(\text{OH})\text{–CH}_2\text{–CH}_3$).
Assigning R and S
Use the Cahn–Ingold–Prelog priorities: 1. Rank the four groups by atomic number of the attached atom (highest = 1). 2. Point the lowest-priority group away. 3. Trace 1 → 2 → 3: clockwise = R, counterclockwise = S.
Diastereomers and Meso Compounds
Diastereomers are stereoisomers that are not mirror images (e.g., cis vs trans 1,2-dimethylcyclopropane). A meso compound has stereocenters but an internal plane of symmetry, making it achiral — 2,3-butanediol's meso form is the classic example.
Practice Problems
- Which of these is chiral: CH3CH2CH2CH3, CH3CHBrCH2CH3, or (CH3)2CHCH3?
- Draw cis- and trans-2-butene and label which is which.
- Assign R or S to glyceraldehyde drawn in a Fischer projection with –CHO on top, –CH2OH on the bottom, –OH on the right, and –H on the left.
- A molecule has two stereocenters and a plane of symmetry. Is it chiral? What is it called?
Answers: 1. CH3CHBrCH2CH3 (2-bromobutane) — C2 has four different groups 2. cis: both CH3 on the same side of the double bond; trans: opposite 3. R — priorities OH(1) > CHO(2) > CH2OH(3) > H(4); 1→2→3 (right → top → bottom) runs counterclockwise, but H sits on a horizontal Fischer bond (a wedge, toward you), so invert the reading → R. This is D-glyceraldehyde = (R)-glyceraldehyde 4. Achiral — a meso compound