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Question: Calculate δHrxn for the following reaction: c(s)+h2o(g)→co(g)+h2(g) use the following reactions and given δh values: c(s)+o2(g)→co2(g), δh= -393.5 kj 2co(g)+o2(g)→2co2(g), δh= -566.0 kj 2h2(g)+o2(g)→2h2o(g), δh= -483.6 kj This is a classic Hess' Law question. Your job is to rearrange the three given reactions so that they add up to (and cancel to) the target reaction. Keep Reaction 1 as is. Reverse Reaction 2 and cut in half. Reverse Reaction 3 and cut in half. c(s)+o2(g)→co2(g), δh= -393.5 kj co2(g)→co(g)+0.5 o2(g), δh= +283.0 kj h2o(g)→h2(g)+0.5 o2(g), δh= +241.8 kj Added together: c(s)+h2o(g)→co(g)+h2(g) Total enthalpy: -393.5 + 283.0 + 241.8 = +131.3 kJ
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Edit, in August 2020: I have decided to answer questions like this one on a new site, www.lewis-structure.com. This molecule in particular was made into my first post, which is at http://lewis-structure.com/ch3f-lewis-structure-and-ch3f-hybridization/
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